numpy.ma.where(condition, x=<no value>, y=<no value>) [source]
Return a masked array with elements from x or y, depending on condition.
Note
When only condition is provided, this function is identical to nonzero. The rest of this documentation covers only the case where all three arguments are provided.
| Parameters: |
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|---|---|
| Returns: |
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See also
numpy.where
nonzero
>>> x = np.ma.array(np.arange(9.).reshape(3, 3), mask=[[0, 1, 0],
... [1, 0, 1],
... [0, 1, 0]])
>>> x
masked_array(
data=[[0.0, --, 2.0],
[--, 4.0, --],
[6.0, --, 8.0]],
mask=[[False, True, False],
[ True, False, True],
[False, True, False]],
fill_value=1e+20)
>>> np.ma.where(x > 5, x, -3.1416)
masked_array(
data=[[-3.1416, --, -3.1416],
[--, -3.1416, --],
[6.0, --, 8.0]],
mask=[[False, True, False],
[ True, False, True],
[False, True, False]],
fill_value=1e+20)
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https://docs.scipy.org/doc/numpy-1.17.0/reference/generated/numpy.ma.where.html