GroupBy.head(self, n=5) [source]
Return first n rows of each group.
Essentially equivalent to .apply(lambda x: x.head(n)), except ignores as_index flag.
| Returns: |
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See also
Series.groupby DataFrame.groupby >>> df = pd.DataFrame([[1, 2], [1, 4], [5, 6]],
... columns=['A', 'B'])
>>> df.groupby('A', as_index=False).head(1)
A B
0 1 2
2 5 6
>>> df.groupby('A').head(1)
A B
0 1 2
2 5 6
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https://pandas.pydata.org/pandas-docs/version/0.25.0/reference/api/pandas.core.groupby.GroupBy.head.html