Series.asof(self, where, subset=None) [source]
Return the last row(s) without any NaNs before where.
The last row (for each element in where, if list) without any NaN is taken. In case of a DataFrame, the last row without NaN considering only the subset of columns (if not None)
New in version 0.19.0: For DataFrame
If there is no good value, NaN is returned for a Series or a Series of NaN values for a DataFrame
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See also
merge_asof
Dates are assumed to be sorted. Raises if this is not the case.
A Series and a scalar where.
>>> s = pd.Series([1, 2, np.nan, 4], index=[10, 20, 30, 40]) >>> s 10 1.0 20 2.0 30 NaN 40 4.0 dtype: float64
>>> s.asof(20) 2.0
For a sequence where, a Series is returned. The first value is NaN, because the first element of where is before the first index value.
>>> s.asof([5, 20]) 5 NaN 20 2.0 dtype: float64
Missing values are not considered. The following is 2.0, not NaN, even though NaN is at the index location for 30.
>>> s.asof(30) 2.0
Take all columns into consideration
>>> df = pd.DataFrame({'a': [10, 20, 30, 40, 50],
... 'b': [None, None, None, None, 500]},
... index=pd.DatetimeIndex(['2018-02-27 09:01:00',
... '2018-02-27 09:02:00',
... '2018-02-27 09:03:00',
... '2018-02-27 09:04:00',
... '2018-02-27 09:05:00']))
>>> df.asof(pd.DatetimeIndex(['2018-02-27 09:03:30',
... '2018-02-27 09:04:30']))
a b
2018-02-27 09:03:30 NaN NaN
2018-02-27 09:04:30 NaN NaN
Take a single column into consideration
>>> df.asof(pd.DatetimeIndex(['2018-02-27 09:03:30',
... '2018-02-27 09:04:30']),
... subset=['a'])
a b
2018-02-27 09:03:30 30.0 NaN
2018-02-27 09:04:30 40.0 NaN
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https://pandas.pydata.org/pandas-docs/version/0.25.0/reference/api/pandas.Series.asof.html